BITSexam
Home
BITSAT-2009 Blog
Free Bitsat sample papers
Contact
Advertise
Search here
Take your test below
1.
e
x
(x + 1)logxdx =
e
x
(xlogx - 1) + c
e
x
(x - logx) + c
e
x
(1 - xlogx) + c
e
x
(logx - x) + c
Have any doubts about BITSAT 2009? Get Complete information about Bitsat-2009 here
Click here
Sample discussions on the BITSexam blog
Subscribe to RSS headline updates from:
Powered by FeedBurner